Question:
Arrange the following in the increasing order of their bond order: O\(_2^-\), O\(_2\), O\(_2^+\), O\(_2^{2-}\)
Arrange the following in the increasing order of their bond order: O\(_2^-\), O\(_2\), O\(_2^+\), O\(_2^{2-}\)
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Removing electrons from antibonding orbitals increases bond order.
Updated On: Apr 7, 2026
- O\(_2^{2-}\), O\(_2^-\), O\(_2\), O\(_2^+\)
- O\(_2^+\), O\(_2\), O\(_2^-\), O\(_2^{2-}\)
- O\(_2^+\), O\(_2\), O\(_2^{2-}\), O\(_2^-\)
- O\(_2^{2-}\), O\(_2\), O\(_2^-\), O\(_2^+\)
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The Correct Option is A
Solution and Explanation
Step 1: Understanding the Concept:
Bond order = \((N_b - N_a)/2\).
Step 2: Detailed Explanation:
O\(_2^{2-}\): BO = 1, O\(_2^-\): BO = 1.5, O\(_2\): BO = 2, O\(_2^+\): BO = 2.5
Increasing order: 1, 1.5, 2, 2.5
Step 3: Final Answer:
O\(_2^{2-}\), O\(_2^-\), O\(_2\), O\(_2^+\).
Bond order = \((N_b - N_a)/2\).
Step 2: Detailed Explanation:
O\(_2^{2-}\): BO = 1, O\(_2^-\): BO = 1.5, O\(_2\): BO = 2, O\(_2^+\): BO = 2.5
Increasing order: 1, 1.5, 2, 2.5
Step 3: Final Answer:
O\(_2^{2-}\), O\(_2^-\), O\(_2\), O\(_2^+\).
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