Question

Arrange the following in the increasing order of their bond order: O\(_2^-\), O\(_2\), O\(_2^+\), O\(_2^{2-}\)

• A. O\(_2^{2-}\), O\(_2^-\), O\(_2\), O\(_2^+\)
• B. O\(_2^+\), O\(_2\), O\(_2^-\), O\(_2^{2-}\)
• C. O\(_2^+\), O\(_2\), O\(_2^{2-}\), O\(_2^-\)
• D. O\(_2^{2-}\), O\(_2\), O\(_2^-\), O\(_2^+\)

Hint:

Removing electrons from antibonding orbitals increases bond order.

Answer 1

The Correct Option is A

Step 1: Understanding the Concept:
Bond order = \((N_b - N_a)/2\).
Step 2: Detailed Explanation:
O\(_2^{2-}\): BO = 1, O\(_2^-\): BO = 1.5, O\(_2\): BO = 2, O\(_2^+\): BO = 2.5
Increasing order: 1, 1.5, 2, 2.5
Step 3: Final Answer:
O\(_2^{2-}\), O\(_2^-\), O\(_2\), O\(_2^+\).