Step 1: Understanding the Question:
We are given hydroxide ion concentration \([OH^-] = 1 \times 10^{-12}\) mol dm\(^{-3}\) and need to find \([H^+]\).
Step 2: Key Formula or Approach:
At 25°C, the ionic product of water is \(K_w = [H^+][OH^-] = 1 \times 10^{-14}\).
Step 3: Detailed Explanation:
\[
[H^+] = \frac{K_w}{[OH^-]} = \frac{1 \times 10^{-14}}{1 \times 10^{-12}} = 1 \times 10^{-2} = 0.01 \text{ mol dm}^{-3}.
\]
Step 4: Final Answer:
The concentration of \(H^+\) ions is 0.01 mol dm\(^{-3}\), option (D).