Question:
The number of six membered carbon rings and five membered carbon rings present in Buckminsterfullerene are \(x\) and \(y\) respectively. The sum of \(x\) and \(y\) is:
The number of six membered carbon rings and five membered carbon rings present in Buckminsterfullerene are \(x\) and \(y\) respectively. The sum of \(x\) and \(y\) is:
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Buckminsterfullerene \((C_{60})\) contains:
\[
12 \text{ pentagons and } 20 \text{ hexagons}
\]
similar to a soccer ball structure.
Updated On: Jun 25, 2026
- \(32\)
- \(23\)
- \(30\)
- \(42\)
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The Correct Option is A
Solution and Explanation
Step 1: Recall the structure of Buckminsterfullerene.
Buckminsterfullerene is: \[ C_{60} \] It has a football-like structure made of pentagonal and hexagonal rings.
Step 2: Number of rings present.
Buckminsterfullerene contains: \[ 12 \] five-membered rings and \[ 20 \] six-membered rings.
Thus, \[ x=20 \] and \[ y=12 \]
Step 3: Find the sum.
\[ x+y=20+12 \] \[ =32 \]
Step 4: Final conclusion.
Hence, \[ \boxed{32} \]
Buckminsterfullerene is: \[ C_{60} \] It has a football-like structure made of pentagonal and hexagonal rings.
Step 2: Number of rings present.
Buckminsterfullerene contains: \[ 12 \] five-membered rings and \[ 20 \] six-membered rings.
Thus, \[ x=20 \] and \[ y=12 \]
Step 3: Find the sum.
\[ x+y=20+12 \] \[ =32 \]
Step 4: Final conclusion.
Hence, \[ \boxed{32} \]
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