Question:
The number of molecules contained in the gas of mass M is ($M_o$ - molar mass, $N_A$ - Avogadro's number)
The number of molecules contained in the gas of mass M is ($M_o$ - molar mass, $N_A$ - Avogadro's number)
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Moles = $\frac{\text{Mass}}{\text{Molar Mass}}$; Molecules = $\text{Moles} \times N_A$.
Updated On: Apr 28, 2026
- $(\frac{M}{M_{o}})\frac{1}{N_{A}}$
- $(\frac{M_{o}}{M})N_{A}$
- $(MM_{\circ})N_{A}$
- $(MM_{\circ})\frac{1}{N_{A}}$
- $(\frac{M}{M_{o}})N_{A}$
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The Correct Option is
Solution and Explanation
Step 1: Concept
The number of moles $n$ is the ratio of given mass $M$ to molar mass $M_o$.
Step 2: Analysis
$n = \frac{M}{M_o}$.
Step 3: Calculation
Total molecules $N = n \times N_A$. Substituting $n$, we get $N = (\frac{M}{M_o})N_A$. Final Answer: (E)
The number of moles $n$ is the ratio of given mass $M$ to molar mass $M_o$.
Step 2: Analysis
$n = \frac{M}{M_o}$.
Step 3: Calculation
Total molecules $N = n \times N_A$. Substituting $n$, we get $N = (\frac{M}{M_o})N_A$. Final Answer: (E)
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