Step 1: Recall the isotopes of hydrogen.
Hydrogen has three isotopes:
\[
^1H \;(\text{Protium})
\]
\[
^2H \;(\text{Deuterium})
\]
\[
^3H \;(\text{Tritium})
\]
Step 2: Form homonuclear hydrogen molecules.
The molecules formed by the same isotopes are:
\[
H_2 \;( ^1H-^1H )
\]
\[
D_2 \;( ^2H-^2H )
\]
\[
T_2 \;( ^3H-^3H )
\]
Thus, there are
\[
3
\]
homonuclear molecules.
Step 3: Form heteronuclear hydrogen molecules.
The molecules formed by different isotopes are:
\[
HD \;( ^1H-^2H )
\]
\[
HT \;( ^1H-^3H )
\]
\[
DT \;( ^2H-^3H )
\]
Thus, there are
\[
3
\]
heteronuclear molecules.
Step 4: Calculate the total number of molecules.
Therefore,
\[
\text{Total molecules}
=
3+3
=
6
\]
Alternatively,
\[
\frac{n(n+1)}{2}
=
\frac{3(3+1)}{2}
=
6
\]
where \(n=3\) isotopes.
Step 5: Final conclusion.
Hence, the number of hydrogen molecules possible from its isotopes is
\[
\boxed{6}
\]
Therefore, option (2) is correct.