Question:

The number of hydrogen molecules possible from its isotopes is

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If an element has \(n\) isotopes, the number of diatomic molecules that can be formed is \[ \frac{n(n+1)}{2} \] For hydrogen (\(n=3\)): \[ \frac{3\times4}{2}=6 \]
Updated On: Jul 18, 2026
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The Correct Option is B

Solution and Explanation

Step 1: Recall the isotopes of hydrogen.
Hydrogen has three isotopes: \[ ^1H \;(\text{Protium}) \] \[ ^2H \;(\text{Deuterium}) \] \[ ^3H \;(\text{Tritium}) \]

Step 2: Form homonuclear hydrogen molecules.
The molecules formed by the same isotopes are: \[ H_2 \;( ^1H-^1H ) \] \[ D_2 \;( ^2H-^2H ) \] \[ T_2 \;( ^3H-^3H ) \] Thus, there are \[ 3 \] homonuclear molecules.

Step 3: Form heteronuclear hydrogen molecules.
The molecules formed by different isotopes are: \[ HD \;( ^1H-^2H ) \] \[ HT \;( ^1H-^3H ) \] \[ DT \;( ^2H-^3H ) \] Thus, there are \[ 3 \] heteronuclear molecules.

Step 4: Calculate the total number of molecules.
Therefore, \[ \text{Total molecules} = 3+3 = 6 \] Alternatively, \[ \frac{n(n+1)}{2} = \frac{3(3+1)}{2} = 6 \] where \(n=3\) isotopes.

Step 5: Final conclusion.
Hence, the number of hydrogen molecules possible from its isotopes is \[ \boxed{6} \] Therefore, option (2) is correct.
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