Question:

The number of cyclic isomers possible for C\(_4\)H\(_6\) with one double bond in the ring is:

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Degree of unsaturation helps quickly determine possible cyclic and double bond combinations.
Updated On: Jun 19, 2026
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The Correct Option is B

Solution and Explanation

Step 1: Understanding degree of unsaturation.
For \(C_4H_6\), degree of unsaturation is: \[ DU = \frac{2C + 2 - H}{2} = \frac{8 + 2 - 6}{2} = 2 \]

Step 2: Given condition interpretation.

One unsaturation is due to a ring and one due to a double bond in the ring.

Step 3: Possible cyclic structures.

Possible cyclic isomers include: - Cyclobutene - Methylcyclopropene (different positional arrangements) Thus total distinct cyclic isomers = 3.

Step 4: Eliminating duplicates.

Structures are counted based on constitutional differences only. Stereoisomers are not considered here.

Step 5: Final conclusion.

Hence total cyclic isomers = 3.
Final Answer: \[ \boxed{3} \]
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