The number of chlorine atoms present in the organic products \(X\) and \(Y\) of the following reactions respectively are: \[ {C6H6 + Cl2 →[Anhyd. AlCl3][dark] X} \] \[ {C6H6 + 3Cl2 →[500K] Y} \]
Step 1: Analyze the first reaction.
Benzene reacts with chlorine in presence of anhydrous aluminium chloride. $$ C_6H_6 + Cl_2 \xrightarrow{anhyd. AlCl_3} C_6H_5Cl + HCl $$ This is an electrophilic substitution reaction.
One hydrogen atom of benzene is replaced by one chlorine atom.
So product X is: $$ C_6H_5Cl $$ It contains 1 chlorine atom.
Step 2: Analyze the second reaction.
Benzene reacts with chlorine in presence of sunlight/high temperature to give addition product. $$ C_6H_6 + 3Cl_2 \rightarrow C_6H_6Cl_6 $$ This is benzene hexachloride.
So product Y is: $$ C_6H_6Cl_6 $$ It contains 6 chlorine atoms.
Step 3: Final answer.
X = 1 chlorine atom
Y = 6 chlorine atoms
Therefore, the correct answer is: 1 and 6.