Question:

The number of chlorine atoms present in the organic products \(X\) and \(Y\) of the following reactions respectively are: \[ {C6H6 + Cl2 →[Anhyd. AlCl3][dark] X} \] \[ {C6H6 + 3Cl2 →[500K] Y} \]

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Benzene with \(Cl_2/AlCl_3\) gives chlorobenzene by substitution, whereas benzene with \(3Cl_2\) gives benzene hexachloride by addition.
Updated On: May 4, 2026
  • 1 and 6
  • 6 and 3
  • 3 and 3
  • 6 and 6
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The Correct Option is A

Solution and Explanation

Step 1: Analyze the first reaction.  

Benzene reacts with chlorine in presence of anhydrous aluminium chloride. $$ C_6H_6 + Cl_2 \xrightarrow{anhyd. AlCl_3} C_6H_5Cl + HCl $$ This is an electrophilic substitution reaction. 
One hydrogen atom of benzene is replaced by one chlorine atom. 

So product X is: $$ C_6H_5Cl $$ It contains 1 chlorine atom


Step 2: Analyze the second reaction. 

Benzene reacts with chlorine in presence of sunlight/high temperature to give addition product. $$ C_6H_6 + 3Cl_2 \rightarrow C_6H_6Cl_6 $$ This is benzene hexachloride. 
So product Y is: $$ C_6H_6Cl_6 $$ It contains 6 chlorine atoms


Step 3: Final answer. 

X = 1 chlorine atom
Y = 6 chlorine atoms 

Therefore, the correct answer is: 1 and 6.

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