Question

Methane reacts with steam at \(1273K\) in the presence of nickel catalyst to form:

• A. \(CO\) and \(H_2\)
• B. \(CO_2\) and \(H_2\)
• C. \(CO\) and \(H_2O\)
• D. \(CO_2\) and \(H_2O\)

Hint:

Steam reforming of methane gives syngas: \(\ce{CH4 + H2O → CO + 3H2}\).

Answer 1

The Correct Option is A

Step 1: Identify the reaction.
Methane reacts with steam at high temperature in presence of nickel catalyst. This reaction is called steam reforming of methane.

Step 2: Write the chemical equation.
\[ \ce{CH4 + H2O ->[Ni][1273K] CO + 3H2} \]

Step 3: Identify the products.
The products are: \[ CO \] and: \[ H_2 \] This mixture is also called synthesis gas or syngas.

Step 4: Final answer.
Therefore, methane reacts with steam to form: \[ CO\text{ and }H_2. \]