The nuclear reaction \(_1\mathrm{H}^1 + _1\mathrm{H}^1 \rightarrow _2\mathrm{He}^4\) (mass of deuteron = 2.0141 amu and of He = 4.0024 amu) is
Show Hint
- fusion reaction releasing 24 MeV energy
- fusion reaction absorbing 24 MeV energy
- fission reaction releasing 0.0258 MeV energy
- fission reaction absorbing 0.0258 MeV energy
The Correct Option is A
Solution and Explanation
Mass defect releases energy via \(E = \Delta m c^2\).
Step 2: Detailed Explanation:
\(\Delta m = 2 \times 2.0141 - 4.0024 = 0.0258\ \mathrm{amu}\)
Energy = \(0.0258 \times 931 = 24\ \mathrm{MeV}\)
This is fusion (light nuclei combining).
Step 3: Final Answer:
Fusion reaction releasing 24 MeV.
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