Question:

The normality of a solution containing 32.5 g of \( \text{(COOH)}_{2} \cdot 2\text{H}_{2}\text{O} \) per 0.5 L is:

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Normality = Molarity $\times$ Basicity (for acids).
Updated On: Apr 8, 2026
  • 10 N
  • 1 N
  • 2 N
  • 0.1 N
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The Correct Option is B

Solution and Explanation

Step 1: Concept
$\text{Normality} = \frac{\text{Weight}}{\text{Eq. wt.} \times \text{Volume (L)}}$.
Step 2: Analysis

* Mol. wt of Oxalic acid $= 126 \text{ g}$. * Eq. wt $= \frac{126}{2} = 63$ (basicity = 2). * $\text{Normality} = \frac{32.5 / 63}{0.5}$. (Note: calculation based on provided source 1885).
Step 3: Conclusion

Normality $= 1 \text{ N}$.
Final Answer: (B)
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