Question:

The solubility product of $\mathrm{Al}_2(\mathrm{SO}_4)_3$ is given by the expression}

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$K_{sp}$ is product of ion concentrations raised to their stoichiometric coefficients.
Updated On: Apr 8, 2026
  • $\mathrm{[Al^{3+}][SO_4^{2-}]}$
  • $\mathrm{[Al^{3+}]^2[SO_4^{2-}]}$
  • $\mathrm{[Al^{3+}]^3[SO_4^{2-}]^2}$
  • $\mathrm{[Al^{3+}]^2[SO_4^{2-}]^3}$
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The Correct Option is D

Solution and Explanation

Step 1: Understanding the Concept:
$K_{sp}$ is product of ion concentrations raised to their stoichiometric coefficients.
Step 2: Detailed Explanation:
$\mathrm{Al_2(SO_4)_3 \rightleftharpoons 2Al^{3+} + 3SO_4^{2-}}$, so $K_{sp} = [\mathrm{Al^{3+}}]^2[\mathrm{SO_4^{2-}}]^3$.
Step 3: Final Answer:
$K_{sp} = [\mathrm{Al^{3+}}]^2[\mathrm{SO_4^{2-}}]^3$.
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