Question:

The minimum value of $x\log x$ is equal to

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$\dfrac{d}{dx}(x\ln x) = \ln x + 1$. The minimum of $x\ln x$ occurs at $x = 1/e$ and equals $-1/e$.
Updated On: Apr 8, 2026
  • $e$
  • $1/e$
  • $-1/e$
  • $2/e$
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
Find the critical point of $f(x) = x\ln x$ for $x>0$ and classify it.
Step 2: Detailed Explanation:
$f'(x) = \ln x + 1 = 0 \Rightarrow x = 1/e$.
$f''(x) = 1/x>0$, so it is a minimum.
$f(1/e) = (1/e)\ln(1/e) = (1/e)(-1) = -1/e$.
Step 3: Final Answer:
Minimum value $= -1/e$.
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