Question:

If $|f(x)|$ is continuous at $x = a$, then $f(x)$

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$|f(x)|$ continuous $\not\Rightarrow$ $f(x)$ continuous. But if $f(x)$ is continuous, then $|f(x)|$ is always continuous.
Updated On: Apr 8, 2026
  • is continuous at $x = a$
  • is continuous at $x = -a$
  • is continuous at $x = \sqrt{a}$
  • need not be continuous at $x = a$
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The Correct Option is D

Solution and Explanation

Step 1: Understanding the Concept:
Continuity of a composed function does not necessarily imply continuity of the inner function.
Step 2: Detailed Explanation:
Counter-example: $f(x) = 1$ for $x \ge 0$ and $f(x) = -1$ for $x<0$.
Then $|f(x)| = 1$ is continuous everywhere, but $f(x)$ is discontinuous at $x = 0$.
Step 3: Final Answer:
Continuity of $|f(x)|$ does not guarantee continuity of $f(x)$.
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