Step 1: Identify the element.
The atomic number is
\[
Z=13
\]
The element with atomic number \(13\) is aluminium:
\[
Al
\]
Its electronic configuration is
\[
1s^2\,2s^2\,2p^6\,3s^2\,3p^1
\]
or
\[
[Ne]3s^2 3p^1
\]
Step 2: Determine the highest oxidation state.
Aluminium has three valence electrons:
\[
3s^2 3p^1
\]
It can lose these three electrons to form:
\[
Al^{3+}
\]
Therefore, the highest oxidation state of aluminium is
\[
+3
\]
Step 3: Determine the maximum covalency.
Aluminium can expand its coordination in compounds and complexes such as fluoroaluminate species.
It can show maximum covalency of
\[
6
\]
For example, in complex species like
\[
[AlF_6]^{3-}
\]
aluminium is bonded to six ligands.
Thus, maximum covalency is
\[
6
\]
Step 4: Final conclusion.
Therefore, the maximum covalency and highest oxidation state are respectively:
\[
\boxed{6,\ +3}
\]
Hence, the correct option is
\[
\boxed{(3)}
\]