Question

The major products formed when one mole of \( \text{CH}_3\text{CH}_2\text{CH}(\text{CH}_3)\text{CH}_2\text{OCH}_2\text{CH}_3 \) is treated with one mole of HI are:

• A. 2-methylbutan-1-ol and iodoethane
• B. ethanol and 2-methylidobutane
• C. 2-methylbutan-2-ol and iodomethane
• D. 2-methylbutan-1-ol and iodomethane
• E. 2-methylbutan-1-ol and ethene

Hint:

HI cleaves ethers into alcohols and alkyl iodides, with the more hindered group forming the alcohol.

Answer 1

The Correct Option is A

The reaction of HI with ethers follows acidic cleavage, where the more hindered alkyl group retains the OH, while the less hindered group forms an iodoalkane. 
- The larger group (2-methylbutyl) forms 2-methylbutan-1-ol. 
- The smaller group (ethyl) forms iodoethane. 
Thus, the major products are 2-methylbutan-1-ol and iodoethane.