Question:
The magnetic moment of the ground state of an atom whose open sub-shell is half-filled with five electrons is
The magnetic moment of the ground state of an atom whose open sub-shell is half-filled with five electrons is
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For magnetic moment in atomic physics, use \( \mu = \sqrt{n(n+2)} \mu_B \) for unpaired electrons.
Updated On: Jan 6, 2026
- \( \sqrt{35} \, \mu_B \)
- \( 35 \, \mu_B \)
- \( 35 \, \mu_B \)
- \( \mu_B \sqrt{35} \)
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The Correct Option is D
Solution and Explanation
Step 1: Identify the ground state of the atom.
The magnetic moment of an atom in a ground state is given by \( \mu = \sqrt{n(n+2)} \mu_B \) where \( n \) is the number of electrons in the unpaired orbital. In this case, the number of unpaired electrons is 5. Thus, we apply the formula: \[ \mu = \sqrt{5(5+2)} \mu_B = \mu_B \sqrt{35} \]
Step 2: Conclusion.
Hence, the correct answer is option (D).
Final Answer: \[ \boxed{\mu_B \sqrt{35}} \]
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