Question:

The linear momentum is increased by 50%, the kinetic energy will increase by

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\(KE \propto p^2\). If \(p\) increases by 50%, \(KE\) becomes \((1.5)^2 = 2.25\) times, i.e., increases by 125%.
Updated On: Apr 8, 2026
  • 50%
  • 100%
  • 125%
  • 25%
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
\(KE = \dfrac{p^2}{2m} \propto p^2\).
Step 2: Detailed Explanation:
New \(p' = 1.5p\)
New \(KE' = \dfrac{(1.5p)^2}{2m} = 2.25 \times \dfrac{p^2}{2m} = 2.25 \times KE\)
Increase \(= (2.25 - 1) \times 100% = 125%\)
Step 3: Final Answer:
KE increases by 125%.
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