Question:

The light pink colour of \([Co(H_2O)_6]^{2+}\) and the deep blue colour of \([CoCl_4]^{2-}\) are due to:

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Centrosymmetric complexes (like octahedral) have pale colors due to Laporte forbidden transitions. Non-centrosymmetric complexes (like tetrahedral) have intense colors.
Updated On: Mar 16, 2026
  • MLCT transition in the first and d-d transition in the second
  • LMCT transition in both
  • d-d transitions in both
  • d-d transition in the first and MLCT transition in the second
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
Colors in transition metal complexes predominantly arise from d-d transitions or Charge Transfer transitions.
Step 2: Detailed Explanation:
1. Hexaaquacobalt(II): An octahedral complex where d-d transitions are Laporte-forbidden. This results in weak absorption and a pale pink color.
2. Tetrachlorocobaltate(II): A tetrahedral complex where the absence of a center of inversion relaxes the Laporte rule, making the d-d transitions much more intense and leading to a deep blue color.
Both colors are caused by the excitation of an electron between split d-orbitals.
Step 3: Final Answer:
The transitions are d-d in both complexes.
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