Question:

The length of a sonometer wire AB is 176 cm. Where should the two bridges be placed from end A to divide the wire into three segments whose fundamental frequencies are in the ratio \(1:2:3\)?

Show Hint

For the same wire and tension, frequency is inversely proportional to length.
Updated On: Nov 12, 2026
  • 90 cm and 140 cm
  • 96 cm and 144 cm
  • 92 cm and 142 cm
  • 94 cm and 48 cm
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept
For the same wire and tension, \(f\propto\dfrac{1}{l}\). Frequencies in the ratio \(1:2:3\) give lengths in the ratio \(1:\dfrac{1}{2}:\dfrac{1}{3}=6:3:2\).

Step 2: Lengths
The 11 parts make 176 cm, so one part is 16 cm.
\(l_{1}=96\ \text{cm}\), \(l_{2}=48\ \text{cm}\), \(l_{3}=32\ \text{cm}\)

Step 3: Bridge positions
First bridge at 96 cm from A and second at \(96+48=144\) cm from A.

Final Answer:
The bridges should be placed at 96 cm and 144 cm from A. \[ \boxed{\text{(B) }\text{96 cm and 144 cm}} \]
Was this answer helpful?
0
0

Top MHT CET Vibrating Wire and Frequency Questions

View More Questions