Question:

The incorrect statement in respect of chromyl chloride test is

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Chromyl Chloride test: Red vapours = $CrO_2Cl_2$; Yellow ppt = $PbCrO_4$. No $Cl_2$ gas.
Updated On: Apr 10, 2026
  • formation of red vapours
  • formation of lead chromate
  • formation of chromyl chloride
  • liberation of chlorine
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The Correct Option is D

Solution and Explanation

Step 1: Test Principle
The chromyl chloride test is used for the qualitative detection of chloride ($Cl^-$) ions.
Step 2: Observations

Heating a chloride salt with $K_2Cr_2O_7$ and conc. $H_2SO_4$ produces reddish-brown vapours of chromyl chloride ($CrO_2Cl_2$). Passing these into $NaOH$ and adding lead acetate forms a yellow precipitate of lead chromate ($PbCrO_4$).
Step 3: Identification of Error

During this reaction, chlorine gas ($Cl_2$) is not liberated.
Final Answer: (d)
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