Question:

\(F_2\) is formed by reacting \(K_2MnF_6\) with:

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\(SbF_5\) is commonly used in fluorine chemistry as a strong oxidising agent.
Updated On: Apr 17, 2026
  • \(SbF_5\)
  • \(MnF_3\)
  • \(KSbF_6\)
  • \(MnF_4\)
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The Correct Option is A

Solution and Explanation

Concept:
•\(K_2MnF_6\) contains \(Mn^{+4}\)
•Strong oxidising agents help liberate \(F_2\)

Step 1:
\[ K_2MnF_6 + SbF_5 \rightarrow KF + MnF_4 + SbF_6^- + F_2 \]

Step 2:

•\(SbF_5\) is a strong fluorinating agent
•Helps release \(F_2\) Final: \[ \Rightarrow SbF_5 \text{ is correct} \]
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