Radioactive decay follows the formula:
\[
N = N_0 e^{-\lambda t}
\]
where the decay constant is related to half-life:
\[
\lambda = \frac{\ln 2}{T_{1/2}}
\]
Given \( T_{1/2} = 12 \) min, the fraction remaining at 28\% decay is:
\[
\frac{N}{N_0} = 0.72
\]
At 82\% decay:
\[
\frac{N}{N_0} = 0.18
\]
Solving for \( t \):
\[
t = \frac{\ln(0.72)}{\ln(0.5)} \times 12
\]
\[
t = \frac{\ln(0.18)}{\ln(0.5)} \times 12
\]
The difference between the two times is 24 minutes.