Question:
An element consists of a mixture of three isotopes A, B, and C of masses \( m_1 \), \( m_2 \), and \( m_3 \) respectively. If the relative abundances of the three isotopes A, B, and C is in the ratio 2:3:5, the average mass of the element is:
An element consists of a mixture of three isotopes A, B, and C of masses \( m_1 \), \( m_2 \), and \( m_3 \) respectively. If the relative abundances of the three isotopes A, B, and C is in the ratio 2:3:5, the average mass of the element is:
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The average atomic mass is found using the weighted sum of isotopic masses divided by the total abundance.
Updated On: Mar 3, 2026
- \( 0.2m_1 + 0.3m_2 + 0.5m_3 \)
- \( 2m_1 + 3m_2 + 5m_3 \)
- \( 0.4m_1 + 0.6m_2 + m_3 \)
- \( 4m_1 + 6m_2 + 10m_3 \)
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The Correct Option is A
Solution and Explanation
The average atomic mass is given by:
\[
M = \frac{2m_1 + 3m_2 + 5m_3}{2+3+5}
\]
\[
= \frac{2m_1 + 3m_2 + 5m_3}{10}
\]
\[
= 0.2m_1 + 0.3m_2 + 0.5m_3
\]
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