Question:
The given diagram shows four processes i.e., isochoric, isobaric, isothermal and adiabatic. The correct assignment of the processes, in the same order is given by :-
The given diagram shows four processes i.e., isochoric, isobaric, isothermal and adiabatic. The correct assignment of the processes, in the same order is given by :-
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Isochoric is the vertical line, isobaric the horizontal line, and the adiabatic curve is steeper than the isothermal through the same point.
Updated On: Nov 5, 2026
- d a b c
- a d b c
- d a c b
- a d c b
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The Correct Option is A
Solution and Explanation
On a P-V diagram: constant volume (isochoric) is a vertical line, so process \(d\); constant pressure (isobaric) is a horizontal line, so process \(a\).
Isothermal: \(PV = \text{const}\), slope \(\left|\frac{dP}{dV}\right| = \frac{P}{V}\). Adiabatic: \(PV^{\gamma} = \text{const}\), slope \(\frac{\gamma P}{V}\), which is larger since \(\gamma > 1\).
So the less steep curve \(b\) is isothermal and the steeper curve \(c\) is adiabatic.
Order (isochoric, isobaric, isothermal, adiabatic) = \(d, a, b, c\).
Answer: (1) d a b c
Isothermal: \(PV = \text{const}\), slope \(\left|\frac{dP}{dV}\right| = \frac{P}{V}\). Adiabatic: \(PV^{\gamma} = \text{const}\), slope \(\frac{\gamma P}{V}\), which is larger since \(\gamma > 1\).
So the less steep curve \(b\) is isothermal and the steeper curve \(c\) is adiabatic.
Order (isochoric, isobaric, isothermal, adiabatic) = \(d, a, b, c\).
Answer: (1) d a b c
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