Question:

The freezing point of a normal 'good average' ice cream mix (10% fat, 11% MSNF, 15% sugar) is about:

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Dissolved solutes (sugars and salts) are the sole reason for the freezing point depression of the mix.
A standard mix with $15\%$ sugar and $11\%$ MSNF consistently freezes around $-2.5^\circ\text{C}$.
  • $-1.0^\circ\text{C}$
  • $-2.5^\circ\text{C}$
  • $-8.5^\circ\text{C}$
  • $-18.0^\circ\text{C}$
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
The freezing point of an ice cream mix is lower than that of pure water ($0^\circ\text{C}$).
This freezing point depression is caused by soluble constituents dissolved in the water phase of the mix, primarily sugars (sucrose, lactose) and mineral salts.
Insoluble ingredients, such as milk fat and proteins, do not contribute to freezing point depression because they are in suspension rather than in true solution.

Step 2: Detailed Explanation:

A standard, average ice cream mix contains:
- $10\%$ milk fat,
- $11\%$ milk solids-not-fat (MSNF, which contains lactose and soluble mineral salts),
- $15\%$ added sucrose (sugar),
- approximately $63.5\%$ water.
The dissolved sugars (sucrose and lactose) and mineral salts depress the freezing point of the water.
Using Raoult's Law for freezing point depression, the theoretical and experimental freezing point of such a typical mix is determined to be approximately $-2.2^\circ\text{C}$ to $-2.8^\circ\text{C}$.
The widely accepted average value in dairy technology literature is $-2.5^\circ\text{C}$.
Thus, the correct option is $-2.5^\circ\text{C}$.

Step 3: Final Answer:

The freezing point of a normal average ice cream mix is about $-2.5^\circ\text{C}$.
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