Question:
The force of interaction between two charges $q₁=6μ C$ and $q₂=2μ C$ is 12 N. If charge $q=-2μ C$ is added to each of the charges, then the new force of interaction is
The force of interaction between two charges $q₁=6μ C$ and $q₂=2μ C$ is 12 N. If charge $q=-2μ C$ is added to each of the charges, then the new force of interaction is
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The force of interaction between two charges $q1=6μ C$ and $q2=2μ C$ is 12 N. If charge $q=-2μ C$ is added to each of the charges, then the new force of interaction is
Updated On: Apr 15, 2026
- $2\times10^{-7}N$
- Zero
- 30 N
- $2\times10^{-3}N$
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The Correct Option is B
Solution and Explanation
Step 1: Analysis
When $-2\mu C$ is added to $q_{2}$ ($2\mu C$), the new charge $q_{2}'$ becomes $2 - 2 = 0$.
Step 2: Calculation
According to Coulomb's Law, force is proportional to the product of charges ($F \propto q_{1}q_{2}$).
Step 3: Conclusion
Since one of the charges is now zero, the force becomes zero.
Final Answer: (b)
When $-2\mu C$ is added to $q_{2}$ ($2\mu C$), the new charge $q_{2}'$ becomes $2 - 2 = 0$.
Step 2: Calculation
According to Coulomb's Law, force is proportional to the product of charges ($F \propto q_{1}q_{2}$).
Step 3: Conclusion
Since one of the charges is now zero, the force becomes zero.
Final Answer: (b)
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