Question:
The expected mass of \({}^{12}_{6}C\) nucleus is (Mass of neutron is 1.00866 u; Mass of proton is 1.00727 u).
The expected mass of \({}^{12}_{6}C\) nucleus is (Mass of neutron is 1.00866 u; Mass of proton is 1.00727 u).
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Expected mass is always slightly greater than the actual nuclear mass due to mass defect.
Updated On: Apr 27, 2026
- 8.0637 น
- 12.0956 u
- 6.0478 u
- 2.0159 น
- 10.0797 u
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Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Step 1: Concept
Expected mass = (Number of protons $\times m_p$) + (Number of neutrons $\times m_n$).
Step 2: Meaning
For ${}_{6}^{12}C$: Protons = 6, Neutrons = $12 - 6 = 6$.
Step 3: Analysis
Expected mass = $6(1.00727) + 6(1.00866) = 6.04362 + 6.05196 = 12.09558 \text{ u}$.
Step 4: Conclusion
Rounding gives 12.0956 u.
Final Answer: (B)
Expected mass = (Number of protons $\times m_p$) + (Number of neutrons $\times m_n$).
Step 2: Meaning
For ${}_{6}^{12}C$: Protons = 6, Neutrons = $12 - 6 = 6$.
Step 3: Analysis
Expected mass = $6(1.00727) + 6(1.00866) = 6.04362 + 6.05196 = 12.09558 \text{ u}$.
Step 4: Conclusion
Rounding gives 12.0956 u.
Final Answer: (B)
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