Question:

The exhausted anion-exchange resin is regenerated with

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Cation Resins use Acids ($H^{+}$); Anion Resins use Bases ($OH^{-}$).
  • dilute $NaOH$ solution
  • dilute $NaCl$ solution
  • dilute $HCl$ solution
  • dilute $Na_{2}SO_{4}$ solution
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The Correct Option is A

Solution and Explanation


Step 1: Concept

Ion-exchange resins must be regenerated once their active sites are occupied by ions from hard water.

Step 2: Meaning

Anion-exchange resins contain basic groups (like $-OH$) that exchange for anions in water. To reverse this, we need a source of hydroxide ions.

Step 3: Analysis

Passing dilute $NaOH$ through the exhausted resin replaces the captured anions with $OH^{-}$ ions, making the resin active again.

Step 4: Conclusion

Anion resins are regenerated with dilute $NaOH$ (Option A).
Final Answer: (A)
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