Question:
In which of the following, the number of bonding electrons and non-bonding electrons are in 3:2 ratio?
In which of the following, the number of bonding electrons and non-bonding electrons are in 3:2 ratio?
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Draw Lewis structures! $N \equiv N$ has 3 lines (6 electrons) and 2 pairs (4 electrons).
Updated On: May 5, 2026
- $N_2$
- $O_2$
- $HCl$
- $F_2$
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The Correct Option is A
Solution and Explanation
Step 1: Concept
Bonding electrons are shared in bonds, and non-bonding (lone pair) electrons are not shared.
Step 2: Meaning
$N_2$ has a triple bond (6 bonding electrons) and each nitrogen has one lone pair (4 non-bonding electrons total).
Step 3: Analysis
Ratio in $N_2 = 6:4 = 3:2$. In $O_2$, it is 4:8 = 1:2. In $F_2$, it is 2:12 = 1:6.
Step 4: Conclusion
$N_2$ matches the 3:2 ratio.
Final Answer: (A)
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