
Given the following resistor network, the resistances are arranged as shown:
From the given circuit:
The resistances between points A, B, C, and D are:
\( 6 \, \Omega \) between A and C, \( 10 \, \Omega \) between B and C, \( 8 \, \Omega \) between C and D, \( 5 \, \Omega \) between B and D, and \( 4 \, \Omega \) between A and D.
First, combine the resistances in parallel and series:
Combine the \( 15 \, \Omega \) resistors in series between points A, C, and B. After the simplification, we get:
\( R_{\text{eq}} = 6 \, \Omega + 5 \, \Omega + 8 \, \Omega = 19 \, \Omega \)
Thus, the correct answer is:
\( R_{\text{eq}} = 19 \, \Omega \)

Thus the correct answer is 19 $\Omega$.
An infinitely long straight wire carrying current $I$ is bent in a planar shape as shown in the diagram. The radius of the circular part is $r$. The magnetic field at the centre $O$ of the circular loop is :
