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the equations of the circle which pass through the
Question:
The equations of the circle which pass through the origin and makes intercepts of lengths
$4$
and
$8$
on the
$x$
and
$y$
-axes respectively are
VITEEE - 2009
VITEEE
Updated On:
Feb 15, 2025
$x^{2}+y^{2}\pm4x\pm8y=0$
$x^{2}+y^{2}\pm2x\pm4y=0$
$x^{2}+y^{2}\pm8x\pm16y=0$
$x^{2}+y^{2}\pm x\pm y=0$
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The Correct Option is
A
Solution and Explanation
In
$\Delta O A C, \,\,\,\,O C^{2}=2^{2}+4^{2}=20$
$\therefore$
Required equation of circle is
$(x \pm 2)^{2}+(y \pm 4)^{2} =20$
$\Rightarrow x^{2}+y^{2} \pm 4 x \pm 8 y =0$
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