Question:
The equation of the plane containing the line
x-x₁=y-y₁m=z-z₁n
is a(x-x₁)+b(y-y₁)+c(z-z₁)=0, then
The equation of the plane containing the line
x-x₁=y-y₁m=z-z₁n
is a(x-x₁)+b(y-y₁)+c(z-z₁)=0, then
Show Hint
Direction ratios of line are perpendicular to plane’s normal.
Updated On: Mar 18, 2026
- a+b m+c z₁=0
- a+b m+c n=0
- a=bm=cn
- x₁+m y₁+n z₁=0
Show Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Step 1: Plane containing line ⇒ normal vector ⟂ direction vector.
Step 2: a+b m+c n=0
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