Step 1: {Check for Reflexivity}
A relation is reflexive if every element is related to itself. In this case, every triangle is congruent to itself. So, \( \triangle A \cong \triangle A \). Thus, the relation R is reflexive.
Step 2: {Check for Symmetry}
A relation is symmetric if for every \( a \) related to \( b \), \( b \) is also related to \( a \). If \( \triangle A \cong \triangle B \), then \( \triangle B \cong \triangle A \). Thus, the relation R is symmetric.
Step 3: {Check for Transitivity}
A relation is transitive if whenever \( a \) is related to \( b \) and \( b \) is related to \( c \), then \( a \) is also related to \( c \). If \( \triangle A \cong \triangle B \) and \( \triangle B \cong \triangle C \), then \( \triangle A \cong \triangle C \). Thus, the relation R is transitive.
Step 4: {Conclusion}
Since the relation R is reflexive, symmetric, and transitive, it is an equivalence relation. Therefore, the correct answer is (D).
Step 1: Understanding the relation
We are given a relation \( R \) on the set of all triangles in a plane, where the relation is defined as "is congruent to." We are tasked with determining whether this relation is an equivalence relation.
Step 2: Definition of an equivalence relation
A relation \( R \) on a set is an equivalence relation if it satisfies the following three properties:
1. Reflexivity: Every element is related to itself. For every triangle \( T \), \( T \) is congruent to \( T \). 2. Symmetry: If \( T_1 \) is related to \( T_2 \) (i.e., \( T_1 \) is congruent to \( T_2 \)), then \( T_2 \) is related to \( T_1 \) (i.e., \( T_2 \) is congruent to \( T_1 \)). 3. Transitivity: If \( T_1 \) is congruent to \( T_2 \) and \( T_2 \) is congruent to \( T_3 \), then \( T_1 \) is congruent to \( T_3 \).
Step 3: Checking for reflexivity
A triangle is congruent to itself. Therefore, for any triangle \( T \), \( T \) is congruent to \( T \). Hence, the relation is reflexive.
Step 4: Checking for symmetry
If triangle \( T_1 \) is congruent to triangle \( T_2 \), then triangle \( T_2 \) is congruent to triangle \( T_1 \). Therefore, the relation is symmetric.
Step 5: Checking for transitivity
If triangle \( T_1 \) is congruent to triangle \( T_2 \), and triangle \( T_2 \) is congruent to triangle \( T_3 \), then triangle \( T_1 \) must be congruent to triangle \( T_3 \). Therefore, the relation is transitive.
Step 6: Conclusion
Since the relation "is congruent to" satisfies all three properties—reflexivity, symmetry, and transitivity—it is an equivalence relation.
Equivalence relation
Which of the following is the correct electronic configuration for \( \text{Oxygen (O)} \)?