Question:
The equation of the circle which passes through the point (4,5) and has its centre at (2,2) is:
The equation of the circle which passes through the point (4,5) and has its centre at (2,2) is:
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Equation of a circle with centre (h,k) is (x-h)²+(y-k)²=r².
Updated On: Mar 20, 2026
- \((x-2)^2+(y-2)^2=13\)
- \((x-2)^2+(y-2)^2=13\)
- \((x)^2+(y)^2=13\)
- (x-4)²+(y-5)²=13
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The Correct Option is A
Solution and Explanation
Step 1: Centre of the circle is (2,2).
Step 2: Radius r is the distance between (2,2) and (4,5): r=√((4-2)²+(5-2)²)=√(4+9)=√(13)
Step 3: Equation of circle: (x-2)²+(y-2)²=13
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