Question

The equation of the circle which passes through the point (4,5) and has its centre at (2,2) is:

• A. \((x-2)^2+(y-2)^2=13\)
• B. \((x-2)^2+(y-2)^2=13\)
• C. \((x)^2+(y)^2=13\)
• D. (x-4)²+(y-5)²=13

Hint:

Equation of a circle with centre (h,k) is (x-h)²+(y-k)²=r².

Answer 1

The Correct Option is A

Step 1: Centre of the circle is (2,2).
Step 2: Radius r is the distance between (2,2) and (4,5): r=√((4-2)²+(5-2)²)=√(4+9)=√(13)
Step 3: Equation of circle: (x-2)²+(y-2)²=13