Question:
For what value of k do the circles x²+y²+5x+3y+7=0 and x²+y²-8x+6y+k=0 cut orthogonally?
For what value of k do the circles x²+y²+5x+3y+7=0 and x²+y²-8x+6y+k=0 cut orthogonally?
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Orthogonal circles satisfy 2(g₁g₂+f₁f₂)=c₁+c₂.
Updated On: Mar 18, 2026
- 16
- −18
- −13
- −10
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Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Step 1: Orthogonality condition. 2(g₁g₂+f₁f₂)=c₁+c₂
Step 2: Substitute coefficients. Solve to get k=-18.
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