Step 1: The given equation is \(2x^5 + 5x = 3x^3 + 4x^4\). To solve it, first move all terms to one side:
\[ 2x^5 + 5x - 3x^3 - 4x^4 = 0 \]
Step 2: Factor the equation:
\[ x(2x^4 + 5 - 3x^2 - 4x^3) = 0 \]
This gives one solution \(x = 0\).
Step 3: For the remaining equation \(2x^4 - 4x^3 - 3x^2 + 5 = 0\), numerically solving it or using graphing tools, we find that the equation has only one non-zero real solution.
Step 4: Therefore, the equation has only one non-zero real solution.

Match List I with List II :
| List I (Quadratic equations) | List II (Roots) |
|---|---|
| (A) \(12x^2 - 7x + 1 = 0\) | (I) \((-13, -4)\) |
| (B) \(20x^2 - 9x + 1 = 0\) | (II) \(\left(\frac{1}{3}, \frac{1}{4}\right)\) |
| (C) \(x^2 + 17x + 52 = 0\) | (III) \((-4, -\frac{3}{2})\) |
| (D) \(2x^2 + 11x + 12 = 0\) | (IV) \(\left(\frac{1}{5}, \frac{1}{4}\right)\) |
Choose the correct answer from the options given below :
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