Step 1: Mass–energy relation
\[ E = mc^2 \]
\[ m = 3.2 \,\mu\text{g} = 3.2 \times 10^{-9} \, \text{kg}, \quad c = 3 \times 10^8 \, \text{m/s} \]
Step 2: Energy in joules
\[ E = (3.2 \times 10^{-9})(3 \times 10^8)^2 \]
\[ E = (3.2 \times 10^{-9})(9 \times 10^{16}) \]
\[ E = 28.8 \times 10^{7} \, \text{J} = 2.88 \times 10^{8} \, \text{J} \]
Step 3: Convert to MeV
\[ 1 \, \text{J} = 6.242 \times 10^{12} \, \text{MeV} \]
\[ E = (2.88 \times 10^{8})(6.242 \times 10^{12}) \]
\[ E \approx 1.8 \times 10^{21} \, \text{MeV} \]
\[ E = 18 \times 10^{20} \, \text{MeV} \]
Final Answer: \( 18 \times 10^{20} \, \text{MeV} \)
Electromagnetic radiation of intensity 0.6 Wn-2 is falling on a blank surface. The radiation pressure on the surface is: