Question:
The empirical formula of an organic compound is $CH_{2}$. The molar mass of the compound is $56g~mol^{-1}$. The organic compound is ________.
The empirical formula of an organic compound is $CH_{2}$. The molar mass of the compound is $56g~mol^{-1}$. The organic compound is ________.
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Molecular Formula = $n \times$ (Empirical Formula).
Updated On: Jun 26, 2026
- n-Butane
- Propene
- Propane
- 2-Methylpropane
- Cyclobutane
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The Correct Option is
Solution and Explanation
Step 1: Concept
Determine the molecular formula by finding the ratio of molar mass to empirical formula mass.
Step 2: Meaning
Empirical formula mass ($CH_2$) = $12 + (2 \times 1) = 14g~mol^{-1}$.
Step 3: Analysis
$n = \text{Molar Mass} / \text{Empirical Mass} = 56 / 14 = 4$. Molecular formula = $(CH_2)_4 = C_4H_8$.
Step 4: Conclusion
Among the options, Cyclobutane has the formula $C_4H_8$. Final Answer: (E)
Determine the molecular formula by finding the ratio of molar mass to empirical formula mass.
Step 2: Meaning
Empirical formula mass ($CH_2$) = $12 + (2 \times 1) = 14g~mol^{-1}$.
Step 3: Analysis
$n = \text{Molar Mass} / \text{Empirical Mass} = 56 / 14 = 4$. Molecular formula = $(CH_2)_4 = C_4H_8$.
Step 4: Conclusion
Among the options, Cyclobutane has the formula $C_4H_8$. Final Answer: (E)
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