Question

The number of electrons in one mole of methane (CH\(_4\)) is:

• A. \( 6.023 \times 10^{23} \)
• B. \( 60.23 \times 10^{23} \)
• C. \( 0.6023 \times 10^{23} \)
• D. \( 602.3 \times 10^{23} \)
• E. \( 6023 \times 10^{23} \)

Hint:

To calculate the total number of electrons in one mole of a compound, multiply the number of electrons in one molecule by Avogadro's number, \( 6.023 \times 10^{23} \).

Answer 1

The Correct Option is B

Step 1: Number of electrons in methane.
In methane (CH\(_4\)), carbon (C) has 6 electrons, and hydrogen (H) has 1 electron. Since there are 4 hydrogen atoms, the total number of electrons in one molecule of methane is: \[ \text{Total electrons} = 6 (\text{from C}) + 4 \times 1 (\text{from H}) = 10 \, \text{electrons per molecule of CH}_4 \]

Step 2: Number of electrons in one mole of methane.
One mole of methane (CH\(_4\)) contains \( 6.023 \times 10^{23} \) molecules (Avogadro's number). Therefore, the total number of electrons in one mole of methane is: \[ \text{Total electrons} = 10 \times 6.023 \times 10^{23} = 60.23 \times 10^{23} \]

Step 3: Conclusion.
Thus, the number of electrons in one mole of methane is \( 60.23 \times 10^{23} \).

Final Answer: (B) \( 60.23 \times 10^{23} \)