Question:
The element that can form multiple bonds with itself from the following is
The element that can form multiple bonds with itself from the following is
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The ability to form \(p\pi-p\pi\) multiple bonds decreases down a group because atomic size increases and orbital overlap becomes less effective.
Updated On: Jun 18, 2026
- Antimony
- Arsenic
- Phosphorus
- Nitrogen
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The Correct Option is D
Solution and Explanation
Step 1: Understand multiple bond formation.
Multiple bonds such as double and triple bonds are formed by effective sideways overlap of \(p\)-orbitals.
Efficient overlap requires small atomic size.
Step 2: Compare the Group 15 elements.
Nitrogen has the smallest atomic size among the given elements.
Therefore, it can form strong \[ N=N \] and \[ N\equiv N \] bonds.
Step 3: Analyze the remaining elements.
Phosphorus, arsenic, and antimony are larger atoms.
Their \(p\)-orbitals are more diffuse and overlap less effectively.
Hence, they generally do not form stable multiple bonds with themselves.
Step 4: Final conclusion.
Therefore, the element that can form multiple bonds with itself is \[ \boxed{\text{Nitrogen}} \] Hence, the correct option is (4).
Multiple bonds such as double and triple bonds are formed by effective sideways overlap of \(p\)-orbitals.
Efficient overlap requires small atomic size.
Step 2: Compare the Group 15 elements.
Nitrogen has the smallest atomic size among the given elements.
Therefore, it can form strong \[ N=N \] and \[ N\equiv N \] bonds.
Step 3: Analyze the remaining elements.
Phosphorus, arsenic, and antimony are larger atoms.
Their \(p\)-orbitals are more diffuse and overlap less effectively.
Hence, they generally do not form stable multiple bonds with themselves.
Step 4: Final conclusion.
Therefore, the element that can form multiple bonds with itself is \[ \boxed{\text{Nitrogen}} \] Hence, the correct option is (4).
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