Question:
The effective length of a column of length \(L\) fixed against rotation and translation at one end and free at the other end is
The effective length of a column of length \(L\) fixed against rotation and translation at one end and free at the other end is
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Effective length factors:
\[
\boxed{
\begin{array}{c|c}
\text{End Condition} & K \hline
\text{Pinned--Pinned} & 1
\text{Fixed--Fixed} & 0.5
\text{Fixed--Pinned} & 0.7
\text{Fixed--Free} & 2
\end{array}
}
\]
Updated On: Jul 24, 2026
- \(0.5L\)
- \(0.7L\)
- \(1.414L\)
- \(2.0L\)
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The Correct Option is D
Solution and Explanation
Step 1: Identify the end condition.
The column is
- Fixed at one end
- Free at the other end
This is a cantilever column.
Step 2: Recall the effective length factor. For a cantilever column, \[ K=2. \] Therefore, \[ L_e=KL=2L. \] Hence, \[ \boxed{2L} \] is the correct answer. Therefore, \[ \boxed{(D)} \] is the correct answer.
Step 2: Recall the effective length factor. For a cantilever column, \[ K=2. \] Therefore, \[ L_e=KL=2L. \] Hence, \[ \boxed{2L} \] is the correct answer. Therefore, \[ \boxed{(D)} \] is the correct answer.
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