Question:

The eccentricity of the conic \(9x^2 - 16y^2 = 144\) is

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Hyperbola: \(e>1\) always.
Updated On: Apr 15, 2026
  • 4/5
  • 4/3
  • 5/4
  • \(\sqrt{7}\)
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The Correct Option is C

Solution and Explanation

Concept: \[ \frac{x^2}{a^2} - \frac{y^2}{b^2} =1,\quad e=\sqrt{1+\frac{b^2}{a^2}} \]

Step 1:
Rewrite.
\[ \frac{x^2}{16} - \frac{y^2}{9} =1 \]

Step 2:
Compute.
\[ e=\sqrt{1+\frac{9}{16}} = \sqrt{\frac{25}{16}} = \frac{5}{4} \]
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