The driver of a car moving towards a rocket launching pad with a speed of 6 m/s observes that the rocket is moving with speed of 10 m/s. The upward speed of the rocket as seen by the stationary observer is
Show Hint
- 4 m/s
- 6 m/s
- 8 m/s
- 11 m/s
The Correct Option is C
Solution and Explanation
Relative velocity is vector difference.
Step 2: Detailed Explanation:
\(v = \sqrt{(10)^2 - (6)^2} = \sqrt{100 - 36} = \sqrt{64} = 8\ \mathrm{m/s}\)
Step 3: Final Answer:
Upward speed is 8 m/s.
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