The power \( P \) of a lens is defined as the reciprocal of its focal length. The dimensional formula for the power of a lens is the same as that of the inverse of length, which is \( [L^{-1}] \). Since power involves only the length dimension, the mass \( M \) and time \( T \) have exponents of 0.
Hence, the dimensional formula for the power of a lens is \( [L^{-1} M^0 T^{0}] \).
The correct option is (A) : \([L^{-1} M^0 T^{0}]\)
The power of a lens is defined as the reciprocal of the focal length (in meters). That is:
$P = \frac{1}{f}$
The dimensional formula for focal length is $[L]$. Hence, the dimensional formula for power is:
$[L^{-1}]$
Since it has no dependence on mass or time, the complete dimensional formula becomes:
Correct answer: [L-1M0T0]
Inductance of a coil with \(10^4\) turns is \(10\,\text{mH}\) and it is connected to a DC source of \(10\,\text{V}\) with internal resistance \(10\,\Omega\). The energy density in the inductor when the current reaches \( \left(\frac{1}{e}\right) \) of its maximum value is \[ \alpha \pi \times \frac{1}{e^2}\ \text{J m}^{-3}. \] The value of \( \alpha \) is _________.
\[ (\mu_0 = 4\pi \times 10^{-7}\ \text{TmA}^{-1}) \]
\(XPQY\) is a vertical smooth long loop having a total resistance \(R\), where \(PX\) is parallel to \(QY\) and the separation between them is \(l\). A constant magnetic field \(B\) perpendicular to the plane of the loop exists in the entire space. A rod \(CD\) of length \(L\,(L>l)\) and mass \(m\) is made to slide down from rest under gravity as shown. The terminal speed acquired by the rod is _______ m/s. 