Question:

The differential equation of the family of curves $y = a\cos\mu x + b\sin\mu x$, where $a$ and $b$ are arbitrary constants, is

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The family $y = a\cos\mu x + b\sin\mu x$ satisfies the simple harmonic equation $y'' + \mu^2 y = 0$. This is a standard result.
Updated On: Apr 8, 2026
  • $\dfrac{d^{2}y}{dx^{2}} + \mu y = 0$
  • $\dfrac{d^{2}y}{dx^{2}} - \mu^{2}y = 0$
  • $\dfrac{d^{2}y}{dx^{2}} + \mu^{2}y = 0$
  • None of these
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
Differentiate twice to eliminate both constants $a$ and $b$.
Step 2: Detailed Explanation:
$y' = -a\mu\sin\mu x + b\mu\cos\mu x$.
$y'' = -a\mu^2\cos\mu x - b\mu^2\sin\mu x = -\mu^2(a\cos\mu x + b\sin\mu x) = -\mu^2 y$.
Hence $y'' + \mu^2 y = 0$.
Step 3: Final Answer:
$\dfrac{d^2y}{dx^2} + \mu^2 y = 0$.
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