Question:

By eliminating the arbitrary constants $A$ and $B$ from $y = Ax^{2} + Bx$, the differential equation obtained is

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To form a differential equation from a family with $n$ arbitrary constants, differentiate $n$ times then eliminate the constants algebraically.
Updated On: Apr 8, 2026
  • $\dfrac{d^{2}y}{dx^{2}} = 0$
  • $x^{2}\dfrac{d^{2}y}{dx^{2}} - 2x\dfrac{dy}{dx} + 2y = 0$
  • $\dfrac{d^{2}y}{dx^{2}} = 0$
  • $x^{2}\dfrac{d^{2}y}{dx^{2}} + y = 0$
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
Differentiate twice to generate two extra equations and eliminate both constants.
Step 2: Detailed Explanation:
$y = Ax^2 + Bx$, $\;y' = 2Ax + B$, $\;y'' = 2A$.
From $y''$: $A = \dfrac{y''}{2}$. From $y'$: $B = y' - 2Ax = y' - xy''$.
Substituting into $y$: $y = \dfrac{y''}{2}x^2 + (y'-xy'')x = xy' - \dfrac{x^2y''}{2}$.
Multiply by $-2$: $x^2y'' - 2xy' + 2y = 0$.
Step 3: Final Answer:
$x^2\dfrac{d^2y}{dx^2} - 2x\dfrac{dy}{dx} + 2y = 0$.
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