Question

The diameter of the objective of a telescope is a, its magnifying power is m and wavelength of light is λ. The resolving power of the telescope is

• A. (1.22λ)/a
• B. (1.22a)/λ
• C. λ m/(1.22a)
• D. a/(1.22λ)

Hint:

Resolving power increases with aperture size.

Answer 1

The Correct Option is D

Step 1: Angular resolution: θ=(1.22λ)/(a)
Step 2: Resolving power =(1)/(θ)=(a)/(1.22λ).