Question

The diameter of the kernel of a circular section of diameter \(d\) is

• A. \(\dfrac{d}{2}\)
• B. \(\dfrac{d}{3}\)
• C. \(\dfrac{d}{4}\)
• D. \(\dfrac{d}{\sqrt{2}}\)

Hint:

Kernel dimensions: \[ \boxed{ \begin{aligned} \text{Rectangle: }&\frac{b}{6}\times\frac{d}{6} \text{Circle: }&\text{Kernel diameter}=\frac{d}{4} \end{aligned} } \]

Answer 1

The Correct Option is C

Step 1: Recall the kernel of a circular section. The kernel (core) is the region within which the line of action of a compressive load must lie so that the entire section remains in compression.

Step 2: State the kernel diameter. For a circular section, \[ \boxed{\text{Radius of kernel}=\frac{d}{8}} \] Therefore, \[ \boxed{\text{Diameter of kernel} = 2\left(\frac{d}{8}\right) = \frac{d}{4}.} \] Hence, \[ \boxed{(C)} \] is the correct answer.