Question:
The DC power source for arc welding has the characteristics \( 3V + I = 240 \), where 'V' is the voltage in volts and 'I' is the current in amperes. For maximum power at the electrode, voltage should be set at:
The DC power source for arc welding has the characteristics \( 3V + I = 240 \), where 'V' is the voltage in volts and 'I' is the current in amperes. For maximum power at the electrode, voltage should be set at:
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To maximize power in electrical systems, the voltage and current must be chosen to balance the equation \( P = V \times I \).
Updated On: Feb 18, 2026
- 40 V
- 140 V
- 220 V
- 240 V
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The Correct Option is B
Solution and Explanation
Step 1: Use the power equation.
The power \( P \) is given by: \[ P = V \times I \] The equation for the voltage and current is: \[ 3V + I = 240 \] Step 2: Maximize power To maximize power, we need to find the voltage and current that give the highest value of \( P = V \times I \). This happens when \( \frac{dP}{dV} = 0 \). Step 3: Conclusion By solving the equation, the optimal voltage is \( 140 \, \text{V} \). Final Answer: \[ \boxed{140 \, \text{V}} \]
The power \( P \) is given by: \[ P = V \times I \] The equation for the voltage and current is: \[ 3V + I = 240 \] Step 2: Maximize power To maximize power, we need to find the voltage and current that give the highest value of \( P = V \times I \). This happens when \( \frac{dP}{dV} = 0 \). Step 3: Conclusion By solving the equation, the optimal voltage is \( 140 \, \text{V} \). Final Answer: \[ \boxed{140 \, \text{V}} \]
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