Step 1: Find the point of intersection.
The given curves are
\[
y=x^2-1
\]
and
\[
y=8x-x^2-9.
\]
At the point of intersection,
\[
x^2-1=8x-x^2-9.
\]
So,
\[
2x^2-8x+8=0.
\]
Dividing by \(2\),
\[
x^2-4x+4=0.
\]
Thus,
\[
(x-2)^2=0.
\]
Hence,
\[
x=2.
\]
Substitute \(x=2\) in
\[
y=x^2-1.
\]
\[
y=2^2-1=4-1=3.
\]
Therefore, the curves intersect at
\[
(2,3).
\]
Step 2: Find the slopes of both curves at \((2,3)\).
For the first curve,
\[
y=x^2-1.
\]
Differentiating with respect to \(x\),
\[
\frac{dy}{dx}=2x.
\]
At \(x=2\),
\[
m_1=2(2)=4.
\]
For the second curve,
\[
y=8x-x^2-9.
\]
Differentiating with respect to \(x\),
\[
\frac{dy}{dx}=8-2x.
\]
At \(x=2\),
\[
m_2=8-2(2)=4.
\]
Step 3: Compare the slopes.
Since
\[
m_1=m_2=4,
\]
the two curves have the same tangent at the point \((2,3)\).
Therefore, the curves touch each other at \((2,3)\).
Step 4: Final conclusion.
Hence,
\[
\boxed{\text{touch each other at }(2,3)}
\]